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Thursday, October 29, 2020

Extra Questions to Solve (Simple Equation)

 More Questions to Practice

(Chapter 4 - VII CBSE Maths)

Question 1:  Write the following statements in the form of equations.
(a) The sum of four times a number and 5 gives a number five times of it.
(b) One-fourth of a number is 2 more than 5.

Question 2:  Convert the following equations in statement form:
(a) 5x = 20
(b) 3y + 7 = 1

Question 3:  If k + 7 = 10, find the value of 9k – 50.

Question 4:  Solve the following equations and check the answers.
Simple Equations Class 7 Extra Questions Maths Chapter 4 Q4

Question 5:  Solve the following equations:
3(y – 2) = 2(y – 1) – 3

Question 6:  If 5 is added to twice a number, the result is 29. Find the number.

Question 7:  If one-third of a number exceeds its one-fourth by 1, find the number.

Question 8:  The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle.

Question 9:  Seven times a number is 12 less than thirteen times the same number. Find the number.

Question 10:  The present age of a son is half the present age of his father. Ten years ago, the father was thrice as old as his son. What are their present age?

Question 11:  The sum of three consecutive multiples of 2 is 18. Find the numbers.

Question 12:  Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 cm, find the length of each side of the triangle.

Question 13:  A man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the remaining 3 km on foot. What is the length of his total journey?


Chapter 4 - Simple Equations (VII CBSE)

Simple Equation

(Chapter 4 in VII CBSE Maths)

Define Equation:

An equation is a condition on a variable.  The word variable means something that can vary (i.e. change its value from time to time).  A variable takes on different numerical values; its value is not fixed. Variables are denoted usually by letters of the alphabet, such as x, y, z, l, m, n, p etc. 

Forming an Expression:

From variables, we form expressions.   The expressions are formed by performing operations like addition, subtraction, multiplication and division on the variables. For instance, from variable x, we can form the expression (4x + 5). For this, first we multiplied x by 4 and then added 5 to the product. Similarly, from y, we form the expression (10y – 20).  For this, we multiplied y by 10 and then subtracted 20 from the product.

Evaluating an Expression:

The value of an expression thus formed depends upon the chosen value of the variable.  As we have already seen, 

        when x = 1, 4x + 5 = 9; 

        when x = 5, 4x + 5 = 25. 

Similarly, 

        when x = 15, 4 x + 5 = 4×15 + 5 = 65; 

        when x = 0, 4 x + 5 = 4 × 0 + 5 = 5

Solution of an Equation:

Equation 4x + 5 = 65 is a condition on the variable x. It states that the value of the expression (4x + 5) is 65. 

Here, the condition is satisfied when x = 15. It is the solution to the equation 4x + 5 = 65. 

When x = 5, 4x + 5 = 25 and not 65. Thus x = 5 is not a solution to the equation.  Similarly, x = 0 is not a solution to the equation. 

No other value of x other than 15 satisfies the condition 4x + 5 = 65.

Components of an Equation:

In an equation there is always an equality sign.  The equality sign shows that the value of the expression to the left of the sign (the left hand side or L.H.S.) is equal to the value of the expression to the right of the sign (the right hand side or R.H.S.). 

In equation 10y – 20 = 50, the L.H.S. is (10y – 20) and the R.H.S. is 50.

If there is some sign other than the equality sign between the L.H.S. and the R.H.S., it is not an equation. Thus, 4x + 5 > 65 is not an equation.

In equations, we often find that the R.H.S. is just a number. But this need not be always so. The R.H.S. of an equation may be an expression containing the variable. 

For example, the equation 

4x + 5 = 6x – 25 

has the expression (4x + 5) on the left and (6x – 25) on the right of the equality sign.

In short, an equation is a condition on a variable. The condition is that two expressions should have equal value. Note that at least one of the two expressions must contain the variable.  An equation remains the same, when the expression on the left and on the right are interchanged.

Exercises:

1.  Write the following statements in the form of equations: 

(i) The sum of three times x and 11 is 32. 

(ii) If you subtract 5 from 6 times a number, you get 7. 

(iii) One fourth of m is 3 more than 7. 

(iv) One third of a number plus 5 is 8.

2.  Convert the following equations in statement form: 

(i) x – 5 = 9 

(ii) 5p = 20 

(iii) 3n + 7 = 1 

(iv) m/5 – 2 = 6

3.  Check whether the value given in the brackets is a solution to the given equation or not: 

(a) n + 5 = 19 (n = 1)                 (b) 7n + 5 = 19 (n = – 2)             (c) 7n + 5 = 19 (n = 2) 

(d) 4p – 3 = 13 (p = 1)               (e) 4p – 3 = 13 (p = – 4)             (f) 4p – 3 = 13 (p = 0)

4.  Solve the following equations by trial and error method: 

(i) 5p + 2 = 17                         (ii) 3m – 14 = 4

5.  Write equations for the following statements: 

(i) The sum of numbers x and 4 is 9.         (ii) The difference between y and 2 is 8. 

(iii) Ten times a is 70.             (iv) The number b divided by 5 gives 6.         (v) Three fourth of t is 15. 

(vi) Seven times m plus 7 gets you 77.         (vii) One fourth of a number minus 4 gives 4. 

(viii) If you take away 6 from 6 times y, you get 60.         (ix) If you add 3 to one third of z, you get 30. 

6. Write the following equations in statement forms:

7.  Raju’s father’s age is 5 years more than three times Raju’s age. Raju’s father is 44 years old. Set up an equation to find Raju’s age

8.  A shopkeeper sells mangoes in two types of boxes, one small and one large. A large box contains as many as 8 small boxes plus 4 loose mangoes. Set up an equation which gives the number of mangoes in each small box. The number of mangoes in a large box is given to be 100.

Tuesday, October 27, 2020

Solved Problems from Simple Linear Equation (VII CBSE)

Find the Value of Unknown using Simple Equation

Question 1: Check whether the value given for x in these questions is a solution to the given equation:

a) 5x + 2 = 12; x = 2 _____________

b) -3 = -x; x = -3 _____________
c) 4x + 3 = -17; x = 3 _____________

d) -3 = 5-3x; x = 3 _____________

Problem 2

Question 2: Mr. Agarwal is 7 times old as his son.  After 10 years, he will be three times as old as his son.  What are the ages of Mr. Agarwal and his son?

Problem 3

Question 3: One number is three times another number.  When the larger number is subtracted from 60, it is 5 less than the smaller number subtracted from 55.  Find the two numbers.

Problem 4

Question 4: Solve for x and then check by substitution.
a)  -5x + 5 = -x + 4
b) 4x - 3 = -3x + 3

Problem 5

Question 5:  If one-third of a number exceeds its one-fourth by 1, find the number.

Problem 6

Question 6:  Seven times a number is 12 less than thirteen times the same number.  Find the number.

Problem 7

Question 7:  The length of a triangle is twice its breadth.  If its perimeter is 18 cm, find its breadth and width.


Thursday, October 22, 2020

Evening Classas on Mathematics!

Classes are conducted on Mathematics to the Students of Class VII (CBSE) thrice a week (Monday, Wednesday and Friday) between 5:30 and 7:00 p.m.

Solve the Algebraic Expressions using Identities

 Exercise 9.5 (1) Solved on 13-02-2022 Exercise 9.5 - 1(iv) Exercise 9.5 - 1(v)